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weight of body is maximum at pole or equator

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Answer: The weight of the body … Earth rotates at around 15 degrees of longitude per hour, or Mach 1.3 along it’s equator. At the poles, at the perfect 90 N or S, that speed of rot... asked Nov 23, 2018 in Gravitation by monuk ( 68.0k points) The thyroid has two side lobes, connected by a bridge (isthmus) in the middle. A 75.0kg man weighs himself at the north pole and at the equator. Answer: % Variation in the weight of a body = % Change in g = 0.7%. Well you can easily understand it logically. near the poles radius of earth is smaller than as in equator. As such we experience more gravitational... How much more weight (in Newton) does he have at the north pole than the equator? Your weight does change slightly from place to place on Earth – at the north pole, one would weigh about 3 N heavier than one near the equator. This "but" is confusing. You can refer to NCERT Solutions for Class 9 Science Chapter 10 Gravitation to revise the concepts in the syllabus effectively and improve your chances of securing high marks in your board exams. The Apparent Weight at the Equator calculator computes the weight of an object on Earth's Equator taking into account the force of gravity pulling the mass down and the centrifugal force from the Earth's rotation pushing outward. Log in. This means that the Earth is wider at the equator than it is from North to South pole. Note that we have focused on the equator and the poles as the extremes, but the same effect applies to all latitudes. If the weight of a body on the earth is 6N, what will be on the moon? Therefore, at the equator, a person of mass 80 kg would have an apparent decrease in mass of (0.00344)(80)= 0.2752 kg. Q16. Have you written down a force balance equation based on the free body diagram? Physics is a branch of science which studies the properties of matter, energy and their mutual relationship. The centrifugal force is maximum at the equator and minimum at the poles. a body weigh more at the equator since earth is not completely round it is an oblate spheroid – a sphere with a bulge around the equator. Rescue Series Carts feature a hygienic ABS countertop with smooth moulded, easy to wipe contours.This affordable ER Cart has a maximum loaded weight … Increases at N-pole and decreases at S-pole Question 24 A body has a weight 90 kg on the earth's surface, the mass of the moon is 1/9 that of the earth's mass and its radius is … However, on the Equator, there is a centrifugal force. Thus, per pound of body weight, mice eat 25 times as much food as people, and yet they don't seem to grow any bigger. Taking the radius of the Earth to be 6.4 x 10^6 m, calculate the centripetal force on a 1 kg mass on the equator. Join now. Weight is measured using a newton-meter. How much will it weight at the equator. The radius of the earth is 6400 km and g = 10 ms^–2. Q16. Thus, the value of g is maximum at the poles and minimum at the equator. It depends upon the value of g. Weight of a body on another planet will be different. Man consumes about one fiftieth of his own weight in food daily, but a mouse will eat half its weight its own weight in a day. The mass of a body remains the same irrespective of the place on the Earth or universe it is - whether at the Poles or the Equator, the mass of a body doesn't change. By default the case 10 is lowered (preferably slightly) in relation to the hospital pole 14 to ensure the biasing apparatus through the attachment exterior surface 44 applies the maximum force against the hospital pole 14. On the Equator, they differ only in magnitude, not in direction, because the centrifugal force directs exactly opposite to the force of gravity there. Fig. Do you weigh more or less at the equator? As we know, The acceleration due to gravity is independent of the mass of the freely falling body. Therefore, the body weighs maximum at poles and minimum at the equator. → g p = 9.81 ms-2, g c = 9.78 m-2. Order this part and others from part-number.info online service. Taking this as a percentage of the previously calculated weight of 784 N, we can gure out that 2.695 N is only 0.344%. If earth stops rotation about its own axis then at the equator the value of \[g\] increases by \[{{\omega }^{2}}R\] and consequently the weight of body lying there increases by \[m{{\omega }^{2}}R\]. (b) g has its maximum value at the equator. Thus, force felt by the object at the pole is greater than the force felt by the same object at the equator. Weight of a body can be zero. Like on a merry-go-round, one is pull away from the Earth. If you weighed 100 pounds at the north pole on a spring scale, at the equator you would weigh 99.65 pounds, or 5.5 ounces less. The weight of a body increases as we move from the equator to the pole. The measured value of g (and apparent weight) also vary because the Earth is spinning. Therefore, the weight of the body at the centre of the earth will be zero. (a) g is same at all places on the surface of earth. http://image.gsfc.nasa.gov/poetry/ask/a11511.html. Calculate the percentage change in the weight of a body when it is taken from the equator to … The amount of heat received at any place depends on the angle at which the sun’s rays strike the surface of the earth and the duration of sunshine. The value of acceleration due to gravity(g) on the surface of the planet or satellite depends on its radius. The weight of an object at the Earth’s South Pole is slightly more than its weight at the Equator because the polar radius of the Earth is slightly less than the equatorial radius. (c) g is less at the earth’s surface than at a height above it or a depth below it. My intuition tells me that weight (as seen on a scale) is the normal force N. On the North Pole, N = W, where W is the weight. 10.21. The weight of a body depends on the force with which it is attracted towards the centre of the Earth. Correct option is . Weight of a body is the force with which it is attracted towards the center of the planet. Because the gravitational pull of the moon is lesser than that of Earth. When the earth rotates, there will arise a ‘centrifugal force’ in it. The value of g is maximum at the poles, so weight at the poles is more. Weight of an object can be zero if R=0. Weight. Analysis. → The g is maximum at poles (g p) and minimum at the equator (g e). Video Explanation. The different conditions of the two locations act to complement each other in exaggerating the difference in perceived weight. Therefore , the weight of an object is zero at the centre of the earth. A) mass is a variable quantity whereas weight is constant: B) mass varies very little at different places whereas weight varies a lot: C) mass is constant but weight increases as the body moves from the poles to the equator: D) mass is a measure of the quantity of matter whereas weight is a force Explain why this is so Match the words in the left column to the appropriate blanks in the sentences on the right. → If the Earth stops rotating about its own axis, the value of g on the poles will remain unchanged but at the equator, it will increase by about 0.35%. If the earth were not rotating then . As the distance of the pole is less than the distance of the equator from the center of the earth, the force of attraction is higher on the body at poles than at the equator. The weight of a body get more at the pole than at the equator of earth - 16903322 1. If I were a betting man I’d have to say we weigh a very tiny bit less at the poles as spherical planet Earth bulges slightly at the equator, so the... Of course (and as noted below, in the comments), it's unlikely that … Weight. away from Earth’s center. This centrifugal force’ will be against the gravitation force in each point in the earth. Increases at south pole and decreases at north pole. WEIGHT IN THE POLES IS MORE THAN THE WEIGHT IN THE EQUATOR – WHY? The true gravity and the weight are … The Earth bulges at the equator, meaning that a body standing on the equator is further from the planet's centre of mass than at the poles. Log in. It is a vector quantity. Learn and free practice physics general knowledge (gk) objective type questions & answers with explanation for all competitve exams and quiz. You can also prove this by your calculations now. The scale exerts an upward force . Throughout the year but the angle decreases as one move towards the pole. Write down the weight of a 50kg mass on the earth. in the non-inertial reference frame at the equator you have [tex] F_g - m \frac{ v^2 }{r} - F_N = 0 [/tex] So the weight that a scale will measure is [tex] F_N = F_g - m \frac{v^2}{r} [/tex] And actually it is really not necessary to use non-inertial reference frame. Equator. A body is weighed by a spring balance to be 1000 N at the north pole. Hence the weight of a body is greater at pole than at the equator. Now the latitude is minimum at the equator and maximum at the poles. For all practical purposes they are the same. At the equator there is slightly less due to gravity being weaker because the diameter at the pole is... 4 ; THE WEIGHT OF AN OBJECT CHANGES ON MOVING FROM THE EQUATOR TO THE POLES. Mass of a body cannot be zero. In more common terms, this person (who as you recall, has a weight of 176 lbs), would have a decrease in weight of It is frequently stated that the value of the acceleration due to gravity at the pole is larger than at the equator because the poles are closer to the center of the earth due to the earth’s oblateness. Due to this, the body weighs more at the poles than at the equator Are you aware that a bathroom scale would indicate the force that the ground exerts on the mass? The NYC 4 and NYC 5 use a dual coil J-type pickup design with a double row of exposed Alnico 2 pole pieces. Melting Polar Ice Will Spike Sea Levels at the Equator Expect higher sea levels in the equatorial Pacific and lower ones near the poles by 2100, according to new research '11405-51 Three distinct voices in this passive soapbar bass pickup, from true vintage J bass, to quiet single coil tone, to maximum output and fullness. Gravitation Class 9 Extra Questions HOTS (Higher Order Thinking Skills) Question 1. Thanks for the A2A. If we see the shape of the Earth, it is flatter at the poles and bulged at the equator. Therefore, the distance of the poles fr... So, you will weigh less on the moon despite having the same mass. This weight is … The radius of the earth at the poles is 6357 km, the radius at the equator is 6378 km. Weight depends upon the value of acceleration due to the gravity of planets. Which of the following statements is true? Log in. We know that the weight of the body is the product of mass and acceleration due to gravity and the acceleration due to gravity increases with the latitude. 1. Recall that the acceleration of a free-falling object near Earth’s surface is approximately [latex] g=9.80\,{\text{m/s}}^{2} [/latex]. If you weighed 100 pounds at the north pole, at the equator you would weigh 99.65 pounds, having shed a whopping 5.5 ounces simply because of your change of location. How much will it weight at the equator. pounds at the equator would add about a pound, and would weigh in at about 201 pounds at the poles. A spring scale that was calibrated on the Pole indicates a mass of 1 kg when its spring is elongated by a force of 9.805 N - the weight of a 1–kg–object on the Pole. As a consequence, weight (i.e nothing but force) of the same object is more at pole than at the equator. the weight reduction at the equator while flying at altitude is relative to the person's sea level weight at the pole. 5. But this force is greater at the pole on account of less distance from the centre of the Earth. Answer. 1. Solution: ‘Centrifugal force’ due to the spinning lowers your body weight by about 0.4 per cent at the equator relative to its weight at the poles. Taking into account both of the above effects, the gravitational acceleration is 9.78 m/s 2 at the equator and 9.83 m/s 2 at the poles, so you weigh about 0.5% more at the poles than at the equator. This force will be ‘0’ in the poles and maximum in the equator. You would weigh more at the poles than at the equator for two reasons : 1) the reduction in the gravitational acceleration at the equator due to the earth's rotation; and 2) the fact that the earth is an oblate sphere (flattened at the poles) which means that the gravitational acceleration is less at the equator due to the increased distance from the center of the earth at the equator. In fact, while the weight of a body will differ on the moon or other planets where the value of acceleration due to gravity, g, is different, its mass will remain the same. If you weighed 100 pounds at the north pole on a spring scale, at the equator you would weigh 99.65 pounds, or 5.5 ounces less. Therefore, the body weighs maximum at poles and minimum at the equator. Answered by Yashvanti Jain | 1st Jun, 2017, 10:58: AM. Any object at the equator is at the maximum distance from the axis. The effective acceleration of gravity at the poles is 980.665 cm/sec/sec while at the equator it is 3.39 cm/sec/sec less due to the centrifugal force. rubna rubna 26.04.2020 Science Secondary School The weight of a body get more at the pole than at the equator of earth 1 See answer rubna is waiting for your help. Weight is the way we usually describe what the scales tell us, but our weight is actually something different. The body experiences a centrifugal force away from the earth due to rotation of the Earth because of which the weight of the body decreases. See also the solution of the task Spring Scale on the Pole and on the Equator). In order that a body of 5 kg weights zero at the equator Since gravity decays according to an inverse square law, the greater distance to the equator from the Earth's centre means that you will weigh a subtly lesser amount than you would at the North or South Pole. The weight of a body depends on the force with which it is attracted towards the centre of the Earth. This is the reading on the scale, and hence it is the apparent weight of the object. Unit of weight is newton or kg-wt. This weight is … An object's apparent weight is slightly less when it is at the equator than when it is at the North Pole. Subject: General Science Exam Prep: AIEEE , Bank Exams , CAT Job Role: Bank PO That means N is "lightened" as such: N = W − C. Recall that the acceleration of a free-falling object near Earth’s surface is approximately [latex] g=9.80\,{\text{m/s}}^{2} [/latex]. A body of mass `10 kg` is taken from equator to pole of the Earth. At the poles, a person has no weight reduction due to centrifugal force. For earth, Rp = 6357 km and Re = 6378 km. Unit of mass is kg. It is slightly compressed at the poles and bulges out at the equator. Question 3: Though the mass of an object remains constant, its weight varies according to its location. 3. In fact, a mass of 1kg of feathers on the north pole will weigh in at a value that is higher than the weight of a 1kg of steel at the equator. http://BigBangPhysics.com Your weight varies over the surface of the Earth and is the least at the equator. The value of g is minimum at the equator, so weight at the equator is less. asked Nov 23, 2018 in Gravitation by monuk ( 68.0k points) Thus, the weight of an object reduces as it moves for poles to the equator and vice versa. → The decrease in g from pole to equator is about 0.35%. However, this difference in weight exists when you consider the same masses at the north pole and at the equator. The Earth is like a slightly (ever so slightly) squished ball. And we know that Earth is not a perfect square. South Pole. … South Pole ️. Join now. Its direction is towards the centre of the Earth or commonly referred to as vertically downwards. But this force is greater at the pole on account of less distance from the centre of the Earth. The weight (mg) points toward Earth’s center. Let’s first consider an object of mass m located at the equator, suspended from a scale (). Interesting and trick question… W = m g “weight” equals the mass of a object times the acceleration of gravity. F= Gm1m2/r2 Force of gravity ( betw... Whereas, an object at the pole will be near the axis. Therefore, the weight of the body at the centre of the earth will be zero. The value of g is maximum at the poles, so weight at the poles is more. Centrifugal force. The earth rotates, and the velocity at the surface from that rotation is greatest at the equator, generating a bit of centrifuga... The radius of the earth at the poles is 6357 km and the radius at the equator is 6378 km. Weight depends upon the value of acceleration due to the gravity of planets. Physics is about an applied mathematics. Stefan, Nice question. Gravity varies around the world, so that a person's weight varies as well. At the poles, the force of gravity is about one-half of one percent greater than at the equator, so that a person weighing in at 200 pounds at the equator would add about a pound, and would weigh in at about 201 pounds at the poles. If you weigh 200 pounds (90.7 kg) at the North Pole, you will weigh 198 pounds (89.8 kg) at the equator. Ask Question. A body is weighed by a spring balance to be 1000 N at the north pole. Assume the Earth is perfectly spherical. NSN 5925-00-810-9352Circuit Breaker part information. While standing at the equator you are further away from the bulk of Earth’s mass than at the poles, so the planet exerts less pull on you. North Pole. And r is more in equator, g will be lower. Example – 02: Find the difference in weight of a body of mass 100 kg on equator and pole. Answer: Weight, W = mg = (50)(9.8) = 490 N. Q17. Yes, you weigh less on the equator than at the North or South Pole, but the difference is small. This non-spherical nature of the Earth means that the gravitational field (and thus the real weight) would be different at the pole vs. the equator. read less Weight of a body is maximum at ….. (a) Moon (b) poles of Earth (c) equator of Earth (d) centre of Earth asked Sep 15, 2020 in Gravitation by Ruksar02 ( 52.5k points) A). The Earth’s spin also causes the planet to bulge, so that at the equator you’re about 21km further from the Earth’s centre of gravity and so weigh around 0.1 per cent less. If the weight of a body on the earth is 6N, what will be on the moon? If Earth bulges at the equator, you would be closer to the center at either pole, hence some 0.662% heavier. Of course this would cancel out on a s... You can simply say that you are accelerated at the equator and you have The surface of the Earth is rotating, so it is not an inertial frame of reference.At latitudes nearer the Equator, the outward centrifugal force produced by Earth's rotation is larger than at polar latitudes. A body of mass `10 kg` is taken from equator to pole of the Earth. Weight of the body is the force with which it is attracted towards the center of the earth. It is flattened at the poles and bulges at the equator. A body weighs slightly more at the poles than at the equator because ... the earth has the maximum speed of rotation al the equator: C) the attractive force at the poles increases due to the ice cap ... and \( W_{E} \) be the weights of a body at the north pole and at the equator respectively. Hence, Weight of the solid body = Weight of liquid displaced by immersed part of the body or VD gr =Vdgl or V Vl d =D 12. Ans: Weight of the body on the equator, on the pole and on latitude 30° are 976.6 N, 980 N and 977.5 N respectively. So, acceleration due to gravity is less at the equator than at the poles. Mass is measured by a pan balance. Imagine first that the Earth’s mass density is constant at any point below the surface and that it is covered in calm water. Now suppose we are in... SI unit of weight is newton (N). Due to this, the body weighs more at the poles than at the equator. Given: m = 100 kg, R = 6400 km = 6.4 × 10 6 m, To find: W P – W E =? Medium. The force causing this acceleration is called the weight of the object, and from Newton’s second law, it has the value mg. The weight of an object is minimum when it is placed at the center of the earth because when an object is in the center, it experiences gravitational pull from all directions. Question 1. R = 6400 km, g = 9.8 m/s 2. Make certain each sentence is complete before submitting your answer. The centripetal acceleration at the equator is given by 4 times pi squared times the radius of the Earth divided by the period of rotation squared (4 timed pi2 times r/T2). So, acceleration due to gravity and hence weight is maximum at the poles and minimum at the equator. The centrifugal force on your body at the equator is 0.034 m/s 2 times the mass of your body. The reason for this is explained below : As we know that g α 1 R 2, where R is the radius of the earth. 4. Therefore W=mg will be maximum at the poles. The same object elongates the spring of the scale by a force of 9.771 N on the Equator and the Pole–calibrated scale thus indicates a mass of 9.772/9.805 = 0.997 kg here. Add your answer and earn points. Yes, but the difference is small, about 0.35%. A mass that weighs 100 kg at the pole will only weight 99.65 kg at the equator. The cause is twofold. The distance from the Earth’s center of mass to the surface at the poles is less than the distance from the Earth’s center of mass to the surface at the equator. B. $\begingroup$ @ahra Have you drawn a free body diagram of the mass at the equator showing the forces acting on the mass, or do you feel that you have advanced beyond the need to use free body diagrams? A body, the mass and the weight of which were already determined at the Equator, is now placed at the Pole. Weight of a body changes from place to place. The effective acceleration of gravity at the poles is 980.665 cm/sec/sec while at the equator it is 3.39 cm/sec/sec less due to the centrifugal force. Instead, it is an oblate spheroid. lower rig … read more The size of your thyroid nodule is greater than 2.0 cm or 20 mm (a size greater than 1.0 cm or 10 mm may also be worrisome as well) It is located in the anterior side of the neck, just under the Adamâ s apple near the larynx and trachea. Find the percentage change in the weight of a body when it is taken from the equator to the poles. Weight of a body is the force with which it is attracted towards the center of the planet. … Answer: Weight, W = mg = (50)(9.8) = 490 N. Q17. Hence the weight of a body is greater at pole than at the equator. Your mass, in grams, however would stay the same because 'grams' is a measure of the resistance of a body to being moved and has nothing to do with acceleration or gravity. Two objects of different masses falling freely near the surface of the moon would In this context, choose the correct statement from the following: a) Mass does not change, weight is maximum b) Mass does not change, weight is minimum c) Both mass and weight are maximum d) Both mass and weight are minimum Answer: The force causing this acceleration is called the weight of the object, and from Newton’s second law, it has the value mg. The value of acceleration due to gravity g is least at the equator and maximum at the poles. Weight is measured by a spring balance. There are two main reasons. One is a real change in weight and the other is an apparent change. By definition, weight is the gravitational attracti... Between the poles of Earth and its equator the gravitational field strength varies since the Earth is not perfectly spherical. So equatorial radius Re is about 21 km greater than the polar radius Rp. This non-spherical nature of the Earth means that the gravitational field (and thus the real weight) would be different at the pole vs. the equator. 48209605 . This counteracts the Earth's gravity to a small degree – up to a maximum of 0.3% at the Equator – and reduces the apparent downward acceleration of falling objects. Note that your body itself does not change. The centrifugal force is maximum at the equator and minimum at the poles. We originally designed these pickups for one of the world’s finest handcrafted basses. The centrifugal force at the poles is zero. Velocity of a body at the equator is `v`.The escape velocity of the body at the poles if the value of acceleration ... the value of acceleration due to gravity is minimum at the equator and maximum at the pole. Ask your question. What is the maximum take-off weight for a Boeing 747-400 aircraft? that is why the places at the equator are more in contact with the core rather than the places at the poles.Since the equator in more closer to the core of the earth it experiences more gravitational force. Weight of a body is maximum at ….. (a) Moon (b) poles of Earth (c) equator of Earth (d) centre of Earth asked Sep 15, 2020 in Gravitation by Ruksar02 ( 52.5k points) Here are some other pages which discuss this phenomenon: https://van.physics.illinois.edu/qa/listing.php?id=186. So some of the force of gravity is being used to make you go round in a circle at the equator (instead of flying of into space) while at the pole this is not needed. Gravitation Class 9 MCQs Questions with Answers. Write down the weight of a 50kg mass on the earth. At the equator the sun’s rays reached the earth’s surface at almost right angles. Weight of the body is the force with which it is attracted towards the center of the earth. As the distance of the pole is less than the distance of the equator from the center of the earth, the force of attraction is higher on the body at poles than at the equator. Hence the weight of a body is greater at pole than at the equator. As the distance of the pole is less than the distance of the equator from the center of the earth, the force of attraction is higher on the body at poles than at the equator. The body experiences a centrifugal force away from the earth due to rotation of the Earth because of which the weight of the body decreases. Answer: The weight of the body … After considering the effect of rotation and elliptical shape of the earth, acceleration due to gravity at the poles and equator are related as Ask your interesting physics related questions for free. Therefore, gravity is maximum at poles and minimum at the equator Let's actually find the value of g in equator and poles Next: What is the SI unit of Thrust and Pressure?→ Class 9; Chapter 10 Class 9 - Gravitation; Extra Questions. Since there is more centrifugal force at the equator to cancel gravity, your overall weight at the equator versus at the poles is even less. The centrifugal force lowers the body's weight at the equator, while the distance from the center of mass at the pole increases weight there. Do I weigh less on the equator than at the North Pole? Yes, you weigh less on the equator than at the North or South Pole, but the difference is small. Note that your body itself does not change. Rather it is the force of gravity and other forces that change as you approach the poles. You weigh slightly less in Mexico City than in New York City, as Mexico City is closer to the equator. (a) is same on equator and poles (b) is least on poles (c) is least on equator (d) increases from pole to equator Answer: (c) It is least at the equator and maximum at the poles due to rotation of earth i.e., it is given by g’=g-co2 R sin0 At poles 0 = 0, So g maximum At equator 0 = 90°, So g maximum. The value of g is minimum at the equator, so weight at the equator is less.

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